Using KDIGO 2012 Clinical Practice Guideline for the Evaluation and Management of Chronic Kidney Disease Volume 3 | Issue 1 | January 2013
Usage
eGFR_child_SCr_BUN(...)
# S3 method for class 'data.frame'
eGFR_child_SCr_BUN(.data, SCr, height, BUN, ...)
# S3 method for class 'units'
eGFR_child_SCr_BUN(SCr, height, BUN, ...)
# S3 method for class 'numeric'
eGFR_child_SCr_BUN(SCr, height, BUN, ...)Arguments
- ...
Further optional arguments
- .data
(data.frame) A data.frame, optional
- SCr
Serum creatinine column name, or vector of units or numeric if
.datais not provided- height
Height of patient column name, or vector of units or numeric if
.datais not provided- BUN
Blood urea nitrogen column name, or vector of units or numeric if
.datais not provided
Details
See https://kdigo.org/guidelines/ckd-evaluation-and-management/ for more details
Examples
eGFR_child_SCr_BUN(eGFR_pt_data,
SCr = "SCr_", height = "height_", BUN = "BUN_",
)
#> Units: [mL/(min*1.73m^2)]
#> [1] NA NA NA NA NA NA NA NA
#> [9] NA NA NA NA NA NA NA NA
#> [17] NA NA NA NA NA NA NA NA
#> [25] NA NA NA NA NA NA NA NA
#> [33] NA NA NA NA NA NA NA NA
#> [41] NA NA NA NA NA NA NA NA
#> [49] NA 148.2122 NA
eGFR_pt_data %>%
dplyr::mutate(eGFR = eGFR_child_SCr_BUN(
SCr = SCr_, height = height_, BUN = BUN_,
))
#> # A tibble: 51 × 11
#> SCr_ SCysC_ Age_ male_ black_ height_ BUN_ eGFR_calc_type_ eGFR_
#> [mg/dl] [mg/L] [years] <lgl> <lgl> [m] [mg/dl] <chr> [mL/…
#> 1 0.5 NA 20 FALSE FALSE NA NA eGFR_adult_SCr 139.
#> 2 NA 0.4 20 FALSE FALSE NA NA eGFR_adult_SCysC 162.
#> 3 0.5 0.4 20 FALSE FALSE NA NA eGFR_adult_SCr_SCy… 167.
#> 4 0.5 NA 30 FALSE TRUE NA NA eGFR_adult_SCr 150.
#> 5 NA 0.4 30 FALSE TRUE NA NA eGFR_adult_SCysC 155.
#> 6 0.5 0.4 30 FALSE TRUE NA NA eGFR_adult_SCr_SCy… 171.
#> 7 0.5 NA 20 FALSE FALSE NA NA eGFR_adult_SCr 139.
#> 8 NA 1.2 20 FALSE FALSE NA NA eGFR_adult_SCysC 66.8
#> 9 0.5 1.2 20 FALSE FALSE NA NA eGFR_adult_SCr_SCy… 96.4
#> 10 0.5 NA 30 FALSE TRUE NA NA eGFR_adult_SCr 150.
#> # ℹ 41 more rows
#> # ℹ 2 more variables: pediatric_ <lgl>, eGFR [mL/(min*1.73m^2)]